Sadlier-Oxford :: Problem of the Day: Fundamentals of Algebra


Mathematics Fundamentals of Algebra Student Center Progress in Mathematics K-8+ Authors National Math Advisory Board Preparing for Fundamentals of Algebra Prerequisite Skills Skills Update Problem of the Day Practice Activities Acceleration Box Practice Activities Vocabulary Activities Alternative Teaching Models Virtual Manipulatives Audio Glossary Enrichment Graphing Calc. Lessons Graphing Calc. Videos Teacher Center Progress in Mathematics K-8+ Sign Up Log In Grade K Grade 1 Grade 2 Grade 3 Grade 4 Grade 5 Grade 6 Fundamentals of Algebra Foundations of Algebra Algebra 1 Family Center Progress in Mathematics K-8+ Authors National Math Advisory Board Prerequisite Skills Preparing for Fundamentals of Algebra Skills Update Problem of the Day Practice Activities Acceleration Box Practice Activities Vocabulary Activities Alternative Teaching Models Virtual Manipulatives Audio Glossary Enrichment Graphing Calc. Lessons Graphing Calc. Videos	K 1 2 3 4 5 6 Fundamentals of Algebra Foundations of Algebra Algebra 1 Print Email Sadlier-Oxford Home » Problem of the Day: Fundamentals of Algebra $Problem of the Day$ Chapter 6, Lesson 10 The distance it takes to stop a car after the driver has applied the brake is in direct proportion to the square of the speed of the car. A traffic-control test revealed that a car traveling at 90 km/h takes about 53 m to stop. Write and solve a proportion that can be used to find the stopping distance for a car that is traveling at 80 km/h.